x^-9=(x-3)(x-5)

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Solution for x^-9=(x-3)(x-5) equation: 



x^-9=(x-3)(x-5)

We move all terms to the left:

x^-9-((x-3)(x-5))=0

We add all the numbers together, and all the variables

x-((x-3)(x-5))-9=0

We multiply parentheses ..

-((+x^2-5x-3x+15))+x-9=0



We calculate terms in parentheses: -((+x^2-5x-3x+15)), so:

(+x^2-5x-3x+15)

We get rid of parentheses

x^2-5x-3x+15

We add all the numbers together, and all the variables

x^2-8x+15

Back to the equation:

-(x^2-8x+15)



We add all the numbers together, and all the variables

x-(x^2-8x+15)-9=0

We get rid of parentheses

-x^2+x+8x-15-9=0

We add all the numbers together, and all the variables

-1x^2+9x-24=0

a = -1; b = 9; c = -24;
Δ = b2-4ac
Δ = 92-4·(-1)·(-24)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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